Solve frac{a^{2}(2^{3}*c^{-2})}{((a/-1)^{3})^{-2}}-2(c/(a^2*2^-1)^2)^-2

$$\frac { a ^ { 2 } ( 2 ^ { 3 } \cdot c ^ { - 2 } ) } { ( ( \frac { a } { - 1 } ) ^ { 3 } ) ^ { - 2 } } - 2 ( \frac { c } { ( a ^ { 2 } \cdot 2 ^ { - 1 } ) ^ { 2 } } ) ^ { - 2 }$$

Evaluate

$$\frac{63a^{8}}{8c^{2}}$$

Short Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and -2 to get -6.

$$\frac{a^{2}\times 2^{3}c^{-2}}{\left(\frac{a}{-1}\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{a^{2}\times 8c^{-2}}{\left(\frac{a}{-1}\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Anything divided by -1 gives its opposite.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times \frac{1}{2}\right)^{2}}\right)^{-2}$$

Expand \left(a^{2}\times \frac{1}{2}\right)^{2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\right)^{2}\times \left(\frac{1}{2}\right)^{2}}\right)^{-2}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{a^{4}\times \left(\frac{1}{2}\right)^{2}}\right)^{-2}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{a^{4}\times \frac{1}{4}}\right)^{-2}$$

To raise \frac{c}{a^{4}\times \frac{1}{4}} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{\left(a^{4}\times \frac{1}{4}\right)^{-2}}$$

Expand \left(a^{4}\times \frac{1}{4}\right)^{-2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{\left(a^{4}\right)^{-2}\times \left(\frac{1}{4}\right)^{-2}}$$

To raise a power to another power, multiply the exponents. Multiply 4 and -2 to get -8.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{a^{-8}\times \left(\frac{1}{4}\right)^{-2}}$$

Calculate \frac{1}{4} to the power of -2 and get 16.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{a^{-8}\times 16}$$

Express 2\times \frac{c^{-2}}{a^{-8}\times 16} as a single fraction.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-\frac{2c^{-2}}{a^{-8}\times 16}$$

Cancel out 2 in both numerator and denominator.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

Expand \left(-a\right)^{-6}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-1\right)^{-6}a^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

Calculate -1 to the power of -6 and get 1.

$$\frac{a^{2}\times 8c^{-2}}{1a^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$8c^{-2}a^{8}-\frac{c^{-2}}{8a^{-8}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 8c^{-2}a^{8} times \frac{8a^{-8}}{8a^{-8}}.

$$\frac{8c^{-2}a^{8}\times 8a^{-8}}{8a^{-8}}-\frac{c^{-2}}{8a^{-8}}$$

Since \frac{8c^{-2}a^{8}\times 8a^{-8}}{8a^{-8}} and \frac{c^{-2}}{8a^{-8}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8c^{-2}a^{8}\times 8a^{-8}-c^{-2}}{8a^{-8}}$$

Do the multiplications in 8c^{-2}a^{8}\times 8a^{-8}-c^{-2}.

$$\frac{64c^{-2}-c^{-2}}{8a^{-8}}$$

Combine like terms in 64c^{-2}-c^{-2}.

$$\frac{63c^{-2}}{8a^{-8}}$$

Expand

$$\frac{63a^{8}}{8c^{2}}$$

Short Solution Steps

To raise a power to another power, multiply the exponents. Multiply 3 and -2 to get -6.

$$\frac{a^{2}\times 2^{3}c^{-2}}{\left(\frac{a}{-1}\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{a^{2}\times 8c^{-2}}{\left(\frac{a}{-1}\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Anything divided by -1 gives its opposite.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times 2^{-1}\right)^{2}}\right)^{-2}$$

Calculate 2 to the power of -1 and get \frac{1}{2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\times \frac{1}{2}\right)^{2}}\right)^{-2}$$

Expand \left(a^{2}\times \frac{1}{2}\right)^{2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{\left(a^{2}\right)^{2}\times \left(\frac{1}{2}\right)^{2}}\right)^{-2}$$

To raise a power to another power, multiply the exponents. Multiply 2 and 2 to get 4.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{a^{4}\times \left(\frac{1}{2}\right)^{2}}\right)^{-2}$$

Calculate \frac{1}{2} to the power of 2 and get \frac{1}{4}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \left(\frac{c}{a^{4}\times \frac{1}{4}}\right)^{-2}$$

To raise \frac{c}{a^{4}\times \frac{1}{4}} to a power, raise both numerator and denominator to the power and then divide.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{\left(a^{4}\times \frac{1}{4}\right)^{-2}}$$

Expand \left(a^{4}\times \frac{1}{4}\right)^{-2}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{\left(a^{4}\right)^{-2}\times \left(\frac{1}{4}\right)^{-2}}$$

To raise a power to another power, multiply the exponents. Multiply 4 and -2 to get -8.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{a^{-8}\times \left(\frac{1}{4}\right)^{-2}}$$

Calculate \frac{1}{4} to the power of -2 and get 16.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-2\times \frac{c^{-2}}{a^{-8}\times 16}$$

Express 2\times \frac{c^{-2}}{a^{-8}\times 16} as a single fraction.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-\frac{2c^{-2}}{a^{-8}\times 16}$$

Cancel out 2 in both numerator and denominator.

$$\frac{a^{2}\times 8c^{-2}}{\left(-a\right)^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

Expand \left(-a\right)^{-6}.

$$\frac{a^{2}\times 8c^{-2}}{\left(-1\right)^{-6}a^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

Calculate -1 to the power of -6 and get 1.

$$\frac{a^{2}\times 8c^{-2}}{1a^{-6}}-\frac{c^{-2}}{8a^{-8}}$$

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$8c^{-2}a^{8}-\frac{c^{-2}}{8a^{-8}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 8c^{-2}a^{8} times \frac{8a^{-8}}{8a^{-8}}.

$$\frac{8c^{-2}a^{8}\times 8a^{-8}}{8a^{-8}}-\frac{c^{-2}}{8a^{-8}}$$

Since \frac{8c^{-2}a^{8}\times 8a^{-8}}{8a^{-8}} and \frac{c^{-2}}{8a^{-8}} have the same denominator, subtract them by subtracting their numerators.

$$\frac{8c^{-2}a^{8}\times 8a^{-8}-c^{-2}}{8a^{-8}}$$

Do the multiplications in 8c^{-2}a^{8}\times 8a^{-8}-c^{-2}.

$$\frac{64c^{-2}-c^{-2}}{8a^{-8}}$$

Combine like terms in 64c^{-2}-c^{-2}.

$$\frac{63c^{-2}}{8a^{-8}}$$