Solve a^2+4a-32/a+8*6a^2-24a/9a-36

$$\frac { a ^ { 2 } + 4 a - 32 } { a + 8 } \cdot \frac { 6 a ^ { 2 } - 24 a } { 9 a - 36 }$$

Evaluate

$$\frac{2a\left(a-4\right)}{3}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}+4a-32}{a+8}.

$$\frac{\left(a-4\right)\left(a+8\right)}{a+8}\times \frac{6a^{2}-24a}{9a-36}$$

Cancel out a+8 in both numerator and denominator.

$$\left(a-4\right)\times \frac{6a^{2}-24a}{9a-36}$$

Factor the expressions that are not already factored in \frac{6a^{2}-24a}{9a-36}.

$$\left(a-4\right)\times \frac{6a\left(a-4\right)}{9\left(a-4\right)}$$

Cancel out 3\left(a-4\right) in both numerator and denominator.

$$\left(a-4\right)\times \frac{2a}{3}$$

Express \left(a-4\right)\times \frac{2a}{3} as a single fraction.

$$\frac{\left(a-4\right)\times 2a}{3}$$

Use the distributive property to multiply a-4 by 2.

$$\frac{\left(2a-8\right)a}{3}$$

Use the distributive property to multiply 2a-8 by a.

$$\frac{2a^{2}-8a}{3}$$

Expand

$$\frac{2a^{2}-8a}{3}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}+4a-32}{a+8}.

$$\frac{\left(a-4\right)\left(a+8\right)}{a+8}\times \frac{6a^{2}-24a}{9a-36}$$

Cancel out a+8 in both numerator and denominator.

$$\left(a-4\right)\times \frac{6a^{2}-24a}{9a-36}$$

Factor the expressions that are not already factored in \frac{6a^{2}-24a}{9a-36}.

$$\left(a-4\right)\times \frac{6a\left(a-4\right)}{9\left(a-4\right)}$$

Cancel out 3\left(a-4\right) in both numerator and denominator.

$$\left(a-4\right)\times \frac{2a}{3}$$

Express \left(a-4\right)\times \frac{2a}{3} as a single fraction.

$$\frac{\left(a-4\right)\times 2a}{3}$$

Use the distributive property to multiply a-4 by 2.

$$\frac{\left(2a-8\right)a}{3}$$

Use the distributive property to multiply 2a-8 by a.

$$\frac{2a^{2}-8a}{3}$$