Solve a^2+2ab+b^2/a^2-b^2*6a/3a+3b

$$\frac { a ^ { 2 } + 2 a b + b ^ { 2 } } { a ^ { 2 } - b ^ { 2 } } \cdot \frac { 6 a } { 3 a + 3 b }$$

Evaluate

$$\frac{2a}{a-b}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}+2ab+b^{2}}{a^{2}-b^{2}}.

$$\frac{\left(a+b\right)^{2}}{\left(a+b\right)\left(a-b\right)}\times \frac{6a}{3a+3b}$$

Cancel out a+b in both numerator and denominator.

$$\frac{a+b}{a-b}\times \frac{6a}{3a+3b}$$

Factor the expressions that are not already factored in \frac{6a}{3a+3b}.

$$\frac{a+b}{a-b}\times \frac{6a}{3\left(a+b\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{a+b}{a-b}\times \frac{2a}{a+b}$$

Multiply \frac{a+b}{a-b} times \frac{2a}{a+b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(a+b\right)\times 2a}{\left(a-b\right)\left(a+b\right)}$$

Cancel out a+b in both numerator and denominator.

$$\frac{2a}{a-b}$$

Expand

$$\frac{2a}{a-b}$$

Short Solution Steps

Factor the expressions that are not already factored in \frac{a^{2}+2ab+b^{2}}{a^{2}-b^{2}}.

$$\frac{\left(a+b\right)^{2}}{\left(a+b\right)\left(a-b\right)}\times \frac{6a}{3a+3b}$$

Cancel out a+b in both numerator and denominator.

$$\frac{a+b}{a-b}\times \frac{6a}{3a+3b}$$

Factor the expressions that are not already factored in \frac{6a}{3a+3b}.

$$\frac{a+b}{a-b}\times \frac{6a}{3\left(a+b\right)}$$

Cancel out 3 in both numerator and denominator.

$$\frac{a+b}{a-b}\times \frac{2a}{a+b}$$

Multiply \frac{a+b}{a-b} times \frac{2a}{a+b} by multiplying numerator times numerator and denominator times denominator.

$$\frac{\left(a+b\right)\times 2a}{\left(a-b\right)\left(a+b\right)}$$

Cancel out a+b in both numerator and denominator.

$$\frac{2a}{a-b}$$