Solve a+c/2b=c

$$\frac { a + c } { 2 b } = c$$

Solve for b

$$\left\{\begin{matrix}b=\frac{a+c}{2c}\text{, }&a\neq -c\text{ and }c\neq 0\\b\neq 0\text{, }&c=0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 2b.

$$a+c=c\times 2b$$

Swap sides so that all variable terms are on the left hand side.

$$c\times 2b=a+c$$

The equation is in standard form.

$$2cb=a+c$$

Divide both sides by 2c.

$$\frac{2cb}{2c}=\frac{a+c}{2c}$$

Dividing by 2c undoes the multiplication by 2c.

$$b=\frac{a+c}{2c}$$

Variable b cannot be equal to 0.

$$b=\frac{a+c}{2c}\text{, }b\neq 0$$

Solve for a

$$a=c\left(2b-1\right)$$

$$b\neq 0$$