Solve a+b/4=L

$$\frac { a + b } { 4 } = L$$

Solve for L

$$L=\frac{a+b}{4}$$

Solution Steps

Divide each term of a+b by 4 to get \frac{1}{4}a+\frac{1}{4}b.

$$\frac{1}{4}a+\frac{1}{4}b=L$$

Swap sides so that all variable terms are on the left hand side.

$$L=\frac{1}{4}a+\frac{1}{4}b$$

Solve for a

$$a=-\left(b-4L\right)$$

Steps for Solving Linear Equation

Divide each term of a+b by 4 to get \frac{1}{4}a+\frac{1}{4}b.

$$\frac{1}{4}a+\frac{1}{4}b=L$$

Subtract \frac{1}{4}b from both sides.

$$\frac{1}{4}a=L-\frac{1}{4}b$$

The equation is in standard form.

$$\frac{1}{4}a=-\frac{b}{4}+L$$

Multiply both sides by 4.

$$\frac{\frac{1}{4}a}{\frac{1}{4}}=\frac{-\frac{b}{4}+L}{\frac{1}{4}}$$

Dividing by \frac{1}{4} undoes the multiplication by \frac{1}{4}.

$$a=\frac{-\frac{b}{4}+L}{\frac{1}{4}}$$

Divide L-\frac{b}{4} by \frac{1}{4} by multiplying L-\frac{b}{4} by the reciprocal of \frac{1}{4}.

$$a=4L-b$$