Solve a+3x^2/b=x^2

$$\frac { a + 3 x ^ { 2 } } { b } = x ^ { 2 }$$

Solve for b

$$\left\{\begin{matrix}b=3+\frac{a}{x^{2}}\text{, }&a\neq -3x^{2}\text{ and }x\neq 0\\b\neq 0\text{, }&x=0\text{ and }a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by b.

$$a+3x^{2}=bx^{2}$$

Swap sides so that all variable terms are on the left hand side.

$$bx^{2}=a+3x^{2}$$

The equation is in standard form.

$$x^{2}b=3x^{2}+a$$

Divide both sides by x^{2}.

$$\frac{x^{2}b}{x^{2}}=\frac{3x^{2}+a}{x^{2}}$$

Dividing by x^{2} undoes the multiplication by x^{2}.

$$b=\frac{3x^{2}+a}{x^{2}}$$

Divide a+3x^{2} by x^{2}.

$$b=3+\frac{a}{x^{2}}$$

Variable b cannot be equal to 0.

$$b=3+\frac{a}{x^{2}}\text{, }b\neq 0$$

Solve for a

$$a=\left(b-3\right)x^{2}$$

$$b\neq 0$$