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Solve for V_1
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2\left(V_{1}-3\right)=V_{1}-2
Multiply both sides of the equation by 10, the least common multiple of 5,10.
2V_{1}-6=V_{1}-2
Use the distributive property to multiply 2 by V_{1}-3.
2V_{1}-6-V_{1}=-2
Subtract V_{1} from both sides.
V_{1}-6=-2
Combine 2V_{1} and -V_{1} to get V_{1}.
V_{1}=-2+6
Add 6 to both sides.
V_{1}=4
Add -2 and 6 to get 4.