Solve V/frac{k+2{3}}=-3

$$\frac { V } { \frac { k + 2 } { 3 } } = - 3$$

Solve for V

$$V=-\left(k+2\right)$$

$$k\neq -2$$

Steps for Solving Linear Equation

Divide V by \frac{k+2}{3} by multiplying V by the reciprocal of \frac{k+2}{3}.

$$\frac{V\times 3}{k+2}=-3$$

Multiply both sides of the equation by k+2.

$$V\times 3=-3\left(k+2\right)$$

Use the distributive property to multiply -3 by k+2.

$$V\times 3=-3k-6$$

The equation is in standard form.

$$3V=-3k-6$$

Divide both sides by 3.

$$\frac{3V}{3}=\frac{-3k-6}{3}$$

Dividing by 3 undoes the multiplication by 3.

$$V=\frac{-3k-6}{3}$$

Divide -3k-6 by 3.

$$V=-k-2$$

Solve for k

$$k=-\left(V+2\right)$$

$$V\neq 0$$

Steps for Solving Linear Equation

Divide V by \frac{k+2}{3} by multiplying V by the reciprocal of \frac{k+2}{3}.

$$\frac{V\times 3}{k+2}=-3$$

Variable k cannot be equal to -2 since division by zero is not defined. Multiply both sides of the equation by k+2.

$$V\times 3=-3\left(k+2\right)$$

Use the distributive property to multiply -3 by k+2.

$$V\times 3=-3k-6$$

Swap sides so that all variable terms are on the left hand side.

$$-3k-6=V\times 3$$

Add 6 to both sides.

$$-3k=V\times 3+6$$

The equation is in standard form.

$$-3k=3V+6$$

Divide both sides by -3.

$$\frac{-3k}{-3}=\frac{3V+6}{-3}$$

Dividing by -3 undoes the multiplication by -3.

$$k=\frac{3V+6}{-3}$$

Divide 6+3V by -3.

$$k=-\left(V+2\right)$$

Variable k cannot be equal to -2.

$$k=-\left(V+2\right)\text{, }k\neq -2$$