Solve for T
T=-\frac{3t}{2}+120
Solve for t
t=-\frac{2T}{3}+80
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2T+3t=240
Multiply both sides of the equation by 240, the least common multiple of 120,80.
2T=240-3t
Subtract 3t from both sides.
\frac{2T}{2}=\frac{240-3t}{2}
Divide both sides by 2.
T=\frac{240-3t}{2}
Dividing by 2 undoes the multiplication by 2.
T=-\frac{3t}{2}+120
Divide 240-3t by 2.
2T+3t=240
Multiply both sides of the equation by 240, the least common multiple of 120,80.
3t=240-2T
Subtract 2T from both sides.
\frac{3t}{3}=\frac{240-2T}{3}
Divide both sides by 3.
t=\frac{240-2T}{3}
Dividing by 3 undoes the multiplication by 3.
t=-\frac{2T}{3}+80
Divide 240-2T by 3.
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