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Solve for H
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\frac{1}{P}H=\sin(\theta )
The equation is in standard form.
\frac{\frac{1}{P}HP}{1}=\frac{\sin(\theta )P}{1}
Divide both sides by P^{-1}.
H=\frac{\sin(\theta )P}{1}
Dividing by P^{-1} undoes the multiplication by P^{-1}.
H=P\sin(\theta )
Divide \sin(\theta ) by P^{-1}.
H=P\sin(\theta )
Variable P cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by P.
P\sin(\theta )=H
Swap sides so that all variable terms are on the left hand side.
\sin(\theta )P=H
The equation is in standard form.
\frac{\sin(\theta )P}{\sin(\theta )}=\frac{H}{\sin(\theta )}
Divide both sides by \sin(\theta ).
P=\frac{H}{\sin(\theta )}
Dividing by \sin(\theta ) undoes the multiplication by \sin(\theta ).
P=\frac{H}{\sin(\theta )}\text{, }P\neq 0
Variable P cannot be equal to 0.