Solve AB/BC+22+294+34=1.7/34

$$\frac { A B } { B C + 22 + 294 + 34 } = \frac { 1.7 } { 34 }$$

Solve for A

$$A=\frac{C}{20}+\frac{35}{2B}$$

$$B\neq 0\text{ and }\left(C=0\text{ or }B\neq -\frac{350}{C}\right)$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 34\left(BC+350\right), the least common multiple of BC+22+294+34,34.

$$34AB=\left(BC+350\right)\times 1.7$$

Use the distributive property to multiply BC+350 by 1.7.

$$34AB=1.7BC+595$$

The equation is in standard form.

$$34BA=\frac{17BC}{10}+595$$

Divide both sides by 34B.

$$\frac{34BA}{34B}=\frac{\frac{17BC}{10}+595}{34B}$$

Dividing by 34B undoes the multiplication by 34B.

$$A=\frac{\frac{17BC}{10}+595}{34B}$$

Divide 595+\frac{17BC}{10} by 34B.

$$A=\frac{C}{20}+\frac{35}{2B}$$

Solve for B

$$B=\frac{35}{2\left(-\frac{C}{20}+A\right)}$$

$$A\neq 0\text{ and }A\neq \frac{C}{20}$$