Solve for A
A=\frac{bh}{6}
b\neq 0
Solve for b
\left\{\begin{matrix}b=\frac{6A}{h}\text{, }&A\neq 0\text{ and }h\neq 0\\b\neq 0\text{, }&h=0\text{ and }A=0\end{matrix}\right.
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6A=bh
Multiply both sides of the equation by 6b, the least common multiple of b,6.
\frac{6A}{6}=\frac{bh}{6}
Divide both sides by 6.
A=\frac{bh}{6}
Dividing by 6 undoes the multiplication by 6.
6A=bh
Variable b cannot be equal to 0 since division by zero is not defined. Multiply both sides of the equation by 6b, the least common multiple of b,6.
bh=6A
Swap sides so that all variable terms are on the left hand side.
hb=6A
The equation is in standard form.
\frac{hb}{h}=\frac{6A}{h}
Divide both sides by h.
b=\frac{6A}{h}
Dividing by h undoes the multiplication by h.
b=\frac{6A}{h}\text{, }b\neq 0
Variable b cannot be equal to 0.
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