Solve for A
A = \frac{273}{10} = 27\frac{3}{10} = 27.3
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50A=21\times 65
Multiply both sides of the equation by 2100, the least common multiple of 42,100.
50A=1365
Multiply 21 and 65 to get 1365.
A=\frac{1365}{50}
Divide both sides by 50.
A=\frac{273}{10}
Reduce the fraction \frac{1365}{50} to lowest terms by extracting and canceling out 5.
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