Solve 998^3-998/998^3+3*998^2+2*99

$$\frac { 998 ^ { 3 } - 998 } { 998 ^ { 3 } + 3 \cdot 998 ^ { 2 } + 2 \cdot 99 }$$

Evaluate

$$\frac{497005497}{498500101}\approx 0.997001798$$

Solution Steps

Calculate 998 to the power of 3 and get 994011992.

$$\frac{994011992-998}{998^{3}+3\times 998^{2}+2\times 99}$$

Subtract 998 from 994011992 to get 994010994.

$$\frac{994010994}{998^{3}+3\times 998^{2}+2\times 99}$$

Calculate 998 to the power of 3 and get 994011992.

$$\frac{994010994}{994011992+3\times 998^{2}+2\times 99}$$

Calculate 998 to the power of 2 and get 996004.

$$\frac{994010994}{994011992+3\times 996004+2\times 99}$$

Multiply 3 and 996004 to get 2988012.

$$\frac{994010994}{994011992+2988012+2\times 99}$$

Add 994011992 and 2988012 to get 997000004.

$$\frac{994010994}{997000004+2\times 99}$$

Multiply 2 and 99 to get 198.

$$\frac{994010994}{997000004+198}$$

Add 997000004 and 198 to get 997000202.

$$\frac{994010994}{997000202}$$

Reduce the fraction \frac{994010994}{997000202} to lowest terms by extracting and canceling out 2.

$$\frac{497005497}{498500101}$$

Factor

$$\frac{3 ^ {3} \cdot 37 \cdot 499 \cdot 997}{11 \cdot 45318191} = 0.9970017979996357$$