Solve 9,8/2x^2-20t-50=0

$$\frac { 9,8 } { 2 } x ^ { 2 } - 20 t - 50 = 0$$

Solve for t

$$t=\frac{49x^{2}}{200}-2,5$$

Steps for Solving Linear Equation

Expand \frac{9,8}{2} by multiplying both numerator and the denominator by 10.

$$\frac{98}{20}x^{2}-20t-50=0$$

Reduce the fraction \frac{98}{20} to lowest terms by extracting and canceling out 2.

$$\frac{49}{10}x^{2}-20t-50=0$$

Subtract \frac{49}{10}x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-20t-50=-\frac{49}{10}x^{2}$$

Add 50 to both sides.

$$-20t=-\frac{49}{10}x^{2}+50$$

The equation is in standard form.

$$-20t=-\frac{49x^{2}}{10}+50$$

Divide both sides by -20.

$$\frac{-20t}{-20}=\frac{-\frac{49x^{2}}{10}+50}{-20}$$

Dividing by -20 undoes the multiplication by -20.

$$t=\frac{-\frac{49x^{2}}{10}+50}{-20}$$

Divide -\frac{49x^{2}}{10}+50 by -20.

$$t=\frac{49x^{2}}{200}-\frac{5}{2}$$

Solve for x

$$x=\frac{\sqrt{\frac{800t+2000}{49}}}{2}$$

$$x=-\frac{\sqrt{\frac{800t+2000}{49}}}{2}\text{, }t\geq -2,5$$