Solve for y
y=1
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3\left(9y+2\right)=7y-4+30
Multiply both sides of the equation by 6, the least common multiple of 2,6.
27y+6=7y-4+30
Use the distributive property to multiply 3 by 9y+2.
27y+6=7y+26
Add -4 and 30 to get 26.
27y+6-7y=26
Subtract 7y from both sides.
20y+6=26
Combine 27y and -7y to get 20y.
20y=26-6
Subtract 6 from both sides.
20y=20
Subtract 6 from 26 to get 20.
y=\frac{20}{20}
Divide both sides by 20.
y=1
Divide 20 by 20 to get 1.
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