Solve for x
x = \frac{4}{3} = 1\frac{1}{3} \approx 1.333333333
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Linear Equation
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\frac { 9 x - 2 } { 3 x - 3 } + \frac { x + 2 } { 1 - x } = 0
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9x-2-3\left(x+2\right)=0
Variable x cannot be equal to 1 since division by zero is not defined. Multiply both sides of the equation by 3\left(x-1\right), the least common multiple of 3x-3,1-x.
9x-2-3x-6=0
Use the distributive property to multiply -3 by x+2.
6x-2-6=0
Combine 9x and -3x to get 6x.
6x-8=0
Subtract 6 from -2 to get -8.
6x=8
Add 8 to both sides. Anything plus zero gives itself.
x=\frac{8}{6}
Divide both sides by 6.
x=\frac{4}{3}
Reduce the fraction \frac{8}{6} to lowest terms by extracting and canceling out 2.
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