Evaluate
\frac{9x^{3}-3y^{3}}{2}
Factor
\frac{3\left(3x^{3}-y^{3}\right)}{2}
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\frac{9x^{3}-3y^{3}}{2}
Since \frac{9x^{3}}{2} and \frac{3y^{3}}{2} have the same denominator, subtract them by subtracting their numerators.
\frac{3\left(3x^{3}-y^{3}\right)}{2}
Factor out \frac{3}{2}.
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