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\frac{9x^{2}y^{4}-4y^{2}}{16}
Factor out \frac{1}{16}.
y^{2}\left(9x^{2}y^{2}-4\right)
Consider 9x^{2}y^{4}-4y^{2}. Factor out y^{2}.
\left(3xy-2\right)\left(3xy+2\right)
Consider 9x^{2}y^{2}-4. Rewrite 9x^{2}y^{2}-4 as \left(3xy\right)^{2}-2^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{y^{2}\left(3xy-2\right)\left(3xy+2\right)}{16}
Rewrite the complete factored expression.