Solve 9rt^2/5p*7p^2q/5r^2t

$$\frac { 9 r t ^ { 2 } } { 5 p } \times \frac { 7 p ^ { 2 } q } { 5 r ^ { 2 } t }$$

Evaluate

$$\frac{63pqt}{25r}$$

Solution Steps

Multiply \frac{9rt^{2}}{5p} times \frac{7p^{2}q}{5r^{2}t} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9rt^{2}\times 7p^{2}q}{5p\times 5r^{2}t}$$

Cancel out prt in both numerator and denominator.

$$\frac{7\times 9pqt}{5\times 5r}$$

Multiply 7 and 9 to get 63.

$$\frac{63pqt}{5\times 5r}$$

Multiply 5 and 5 to get 25.

$$\frac{63pqt}{25r}$$

Differentiate w.r.t. q

$$\frac{63pt}{25r}$$