Solve 9b-5/b-1-7b-3/b-1

$$\frac { 9 b - 5 } { b - 1 } - \frac { 7 b - 3 } { b - 1 }$$

Evaluate

$$2$$

Short Solution Steps

Since \frac{9b-5}{b-1} and \frac{7b-3}{b-1} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9b-5-\left(7b-3\right)}{b-1}$$

Do the multiplications in 9b-5-\left(7b-3\right).

$$\frac{9b-5-7b+3}{b-1}$$

Combine like terms in 9b-5-7b+3.

$$\frac{2b-2}{b-1}$$

Factor the expressions that are not already factored in \frac{2b-2}{b-1}.

$$\frac{2\left(b-1\right)}{b-1}$$

Cancel out b-1 in both numerator and denominator.

$$2$$

Factor

$$2$$