Solve 9b^4/2g^3*4g^4/3b^2

$$\frac { 9 b ^ { 4 } } { 2 g ^ { 3 } } \times \frac { 4 g ^ { 4 } } { 3 b ^ { 2 } }$$

Evaluate

$$6gb^{2}$$

Solution Steps

Multiply \frac{9b^{4}}{2g^{3}} times \frac{4g^{4}}{3b^{2}} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9b^{4}\times 4g^{4}}{2g^{3}\times 3b^{2}}$$

Cancel out 2\times 3b^{2}g^{3} in both numerator and denominator.

$$2\times 3gb^{2}$$

Multiply 2 and 3 to get 6.

$$6gb^{2}$$

Differentiate w.r.t. g

$$6b^{2}$$