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\frac{\left(9-5i\right)\left(5-7i\right)}{\left(5+7i\right)\left(5-7i\right)}
Multiply both numerator and denominator by the complex conjugate of the denominator, 5-7i.
\frac{\left(9-5i\right)\left(5-7i\right)}{5^{2}-7^{2}i^{2}}
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
\frac{\left(9-5i\right)\left(5-7i\right)}{74}
By definition, i^{2} is -1. Calculate the denominator.
\frac{9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)i^{2}}{74}
Multiply complex numbers 9-5i and 5-7i like you multiply binomials.
\frac{9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)\left(-1\right)}{74}
By definition, i^{2} is -1.
\frac{45-63i-25i-35}{74}
Do the multiplications in 9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)\left(-1\right).
\frac{45-35+\left(-63-25\right)i}{74}
Combine the real and imaginary parts in 45-63i-25i-35.
\frac{10-88i}{74}
Do the additions in 45-35+\left(-63-25\right)i.
\frac{5}{37}-\frac{44}{37}i
Divide 10-88i by 74 to get \frac{5}{37}-\frac{44}{37}i.
Re(\frac{\left(9-5i\right)\left(5-7i\right)}{\left(5+7i\right)\left(5-7i\right)})
Multiply both numerator and denominator of \frac{9-5i}{5+7i} by the complex conjugate of the denominator, 5-7i.
Re(\frac{\left(9-5i\right)\left(5-7i\right)}{5^{2}-7^{2}i^{2}})
Multiplication can be transformed into difference of squares using the rule: \left(a-b\right)\left(a+b\right)=a^{2}-b^{2}.
Re(\frac{\left(9-5i\right)\left(5-7i\right)}{74})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)i^{2}}{74})
Multiply complex numbers 9-5i and 5-7i like you multiply binomials.
Re(\frac{9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)\left(-1\right)}{74})
By definition, i^{2} is -1.
Re(\frac{45-63i-25i-35}{74})
Do the multiplications in 9\times 5+9\times \left(-7i\right)-5i\times 5-5\left(-7\right)\left(-1\right).
Re(\frac{45-35+\left(-63-25\right)i}{74})
Combine the real and imaginary parts in 45-63i-25i-35.
Re(\frac{10-88i}{74})
Do the additions in 45-35+\left(-63-25\right)i.
Re(\frac{5}{37}-\frac{44}{37}i)
Divide 10-88i by 74 to get \frac{5}{37}-\frac{44}{37}i.
\frac{5}{37}
The real part of \frac{5}{37}-\frac{44}{37}i is \frac{5}{37}.