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\frac{\left(9-4i\right)i}{1i^{2}}
Multiply both numerator and denominator by imaginary unit i.
\frac{\left(9-4i\right)i}{-1}
By definition, i^{2} is -1. Calculate the denominator.
\frac{9i-4i^{2}}{-1}
Multiply 9-4i times i.
\frac{9i-4\left(-1\right)}{-1}
By definition, i^{2} is -1.
\frac{4+9i}{-1}
Do the multiplications in 9i-4\left(-1\right). Reorder the terms.
-4-9i
Divide 4+9i by -1 to get -4-9i.
Re(\frac{\left(9-4i\right)i}{1i^{2}})
Multiply both numerator and denominator of \frac{9-4i}{i} by imaginary unit i.
Re(\frac{\left(9-4i\right)i}{-1})
By definition, i^{2} is -1. Calculate the denominator.
Re(\frac{9i-4i^{2}}{-1})
Multiply 9-4i times i.
Re(\frac{9i-4\left(-1\right)}{-1})
By definition, i^{2} is -1.
Re(\frac{4+9i}{-1})
Do the multiplications in 9i-4\left(-1\right). Reorder the terms.
Re(-4-9i)
Divide 4+9i by -1 to get -4-9i.
-4
The real part of -4-9i is -4.