Solve 9/9(2-6)(2-8)-9(2-6)/9(2-6)(2-8)=(2-8)/9(2-6)(2*8)

$$\frac { 9 } { 9 ( 2 - 6 ) ( 2 - 8 ) } - \frac { 9 ( 2 - 6 ) } { 9 ( 2 - 6 ) ( 2 - 8 ) } = \frac { ( 2 - 8 ) } { 9 ( 2 - 6 ) ( 2 \cdot 8 ) }$$

Verify

Solution Steps

Subtract 6 from 2 to get -4.

$$\frac{9}{9\left(-4\right)\left(2-8\right)}-\frac{9\left(2-6\right)}{9\left(2-6\right)\left(2-8\right)}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Multiply 9 and -4 to get -36.

$$\frac{9}{-36\left(2-8\right)}-\frac{9\left(2-6\right)}{9\left(2-6\right)\left(2-8\right)}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Subtract 8 from 2 to get -6.

$$\frac{9}{-36\left(-6\right)}-\frac{9\left(2-6\right)}{9\left(2-6\right)\left(2-8\right)}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Multiply -36 and -6 to get 216.

$$\frac{9}{216}-\frac{9\left(2-6\right)}{9\left(2-6\right)\left(2-8\right)}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Reduce the fraction \frac{9}{216} to lowest terms by extracting and canceling out 9.

$$\frac{1}{24}-\frac{9\left(2-6\right)}{9\left(2-6\right)\left(2-8\right)}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Cancel out 9\left(2-6\right) in both numerator and denominator.

$$\frac{1}{24}-\frac{1}{2-8}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Subtract 8 from 2 to get -6.

$$\frac{1}{24}-\frac{1}{-6}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Fraction \frac{1}{-6} can be rewritten as -\frac{1}{6} by extracting the negative sign.

$$\frac{1}{24}-\left(-\frac{1}{6}\right)=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

The opposite of -\frac{1}{6} is \frac{1}{6}.

$$\frac{1}{24}+\frac{1}{6}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Least common multiple of 24 and 6 is 24. Convert \frac{1}{24} and \frac{1}{6} to fractions with denominator 24.

$$\frac{1}{24}+\frac{4}{24}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Since \frac{1}{24} and \frac{4}{24} have the same denominator, add them by adding their numerators.

$$\frac{1+4}{24}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Add 1 and 4 to get 5.

$$\frac{5}{24}=\frac{2-8}{9\left(2-6\right)\times 2\times 8}$$

Subtract 8 from 2 to get -6.

$$\frac{5}{24}=\frac{-6}{9\left(2-6\right)\times 2\times 8}$$

Subtract 6 from 2 to get -4.

$$\frac{5}{24}=\frac{-6}{9\left(-4\right)\times 2\times 8}$$

Multiply 9 and -4 to get -36.

$$\frac{5}{24}=\frac{-6}{-36\times 2\times 8}$$

Multiply -36 and 2 to get -72.

$$\frac{5}{24}=\frac{-6}{-72\times 8}$$

Multiply -72 and 8 to get -576.

$$\frac{5}{24}=\frac{-6}{-576}$$

Reduce the fraction \frac{-6}{-576} to lowest terms by extracting and canceling out -6.

$$\frac{5}{24}=\frac{1}{96}$$

Least common multiple of 24 and 96 is 96. Convert \frac{5}{24} and \frac{1}{96} to fractions with denominator 96.

$$\frac{20}{96}=\frac{1}{96}$$

Compare \frac{20}{96} and \frac{1}{96}.

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