Solve 9/8div3/4=4/8*4/3=frac{3}{2}

$$\frac { 9 } { 8 } \div \frac { 3 } { 4 } = \frac { 4 } { 8 } \times \frac { 4 } { 3 } = \frac { 3 } { 2 }$$

Verify

Solution Steps

Divide \frac{9}{8} by \frac{3}{4} by multiplying \frac{9}{8} by the reciprocal of \frac{3}{4}.

$$\frac{9}{8}\times \frac{4}{3}=\frac{4}{8}\times \frac{4}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Multiply \frac{9}{8} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 4}{8\times 3}=\frac{4}{8}\times \frac{4}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Do the multiplications in the fraction \frac{9\times 4}{8\times 3}.

$$\frac{36}{24}=\frac{4}{8}\times \frac{4}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Reduce the fraction \frac{36}{24} to lowest terms by extracting and canceling out 12.

$$\frac{3}{2}=\frac{4}{8}\times \frac{4}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\frac{3}{2}=\frac{1}{2}\times \frac{4}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Multiply \frac{1}{2} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\frac{3}{2}=\frac{1\times 4}{2\times 3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Do the multiplications in the fraction \frac{1\times 4}{2\times 3}.

$$\frac{3}{2}=\frac{4}{6}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\frac{3}{2}=\frac{2}{3}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Least common multiple of 2 and 3 is 6. Convert \frac{3}{2} and \frac{2}{3} to fractions with denominator 6.

$$\frac{9}{6}=\frac{4}{6}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Compare \frac{9}{6} and \frac{4}{6}.

$$\text{false}\text{ and }\frac{4}{8}\times \frac{4}{3}=\frac{3}{2}$$

Reduce the fraction \frac{4}{8} to lowest terms by extracting and canceling out 4.

$$\text{false}\text{ and }\frac{1}{2}\times \frac{4}{3}=\frac{3}{2}$$

Multiply \frac{1}{2} times \frac{4}{3} by multiplying numerator times numerator and denominator times denominator.

$$\text{false}\text{ and }\frac{1\times 4}{2\times 3}=\frac{3}{2}$$

Do the multiplications in the fraction \frac{1\times 4}{2\times 3}.

$$\text{false}\text{ and }\frac{4}{6}=\frac{3}{2}$$

Reduce the fraction \frac{4}{6} to lowest terms by extracting and canceling out 2.

$$\text{false}\text{ and }\frac{2}{3}=\frac{3}{2}$$

Least common multiple of 3 and 2 is 6. Convert \frac{2}{3} and \frac{3}{2} to fractions with denominator 6.

$$\text{false}\text{ and }\frac{4}{6}=\frac{9}{6}$$

Compare \frac{4}{6} and \frac{9}{6}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$