Solve 9/6+1/9+2/3

$$\frac { 9 } { 6 } + \frac { 1 } { 9 } + \frac { 2 } { 3 }$$

Evaluate

$$\frac{41}{18}\approx 2.277777778$$

Solution Steps

Reduce the fraction \frac{9}{6} to lowest terms by extracting and canceling out 3.

$$\frac{3}{2}+\frac{1}{9}+\frac{2}{3}$$

Least common multiple of 2 and 9 is 18. Convert \frac{3}{2} and \frac{1}{9} to fractions with denominator 18.

$$\frac{27}{18}+\frac{2}{18}+\frac{2}{3}$$

Since \frac{27}{18} and \frac{2}{18} have the same denominator, add them by adding their numerators.

$$\frac{27+2}{18}+\frac{2}{3}$$

Add 27 and 2 to get 29.

$$\frac{29}{18}+\frac{2}{3}$$

Least common multiple of 18 and 3 is 18. Convert \frac{29}{18} and \frac{2}{3} to fractions with denominator 18.

$$\frac{29}{18}+\frac{12}{18}$$

Since \frac{29}{18} and \frac{12}{18} have the same denominator, add them by adding their numerators.

$$\frac{29+12}{18}$$

Add 29 and 12 to get 41.

$$\frac{41}{18}$$

Factor

$$\frac{41}{2 \cdot 3 ^ {2}} = 2\frac{5}{18} = 2.2777777777777777$$