Solve 9/5x+12/5(40x)-9=79.8

$$\frac { 9 } { 5 } x + \frac { 12 } { 5 } ( 40 x ) - 9 = 79.8$$

Solve for x

$$x=\frac{148}{163}\approx 0.90797546$$

Steps for Solving Linear Equation

Express \frac{12}{5}\times 40 as a single fraction.

$$\frac{9}{5}x+\frac{12\times 40}{5}x-9=79.8$$

Multiply 12 and 40 to get 480.

$$\frac{9}{5}x+\frac{480}{5}x-9=79.8$$

Divide 480 by 5 to get 96.

$$\frac{9}{5}x+96x-9=79.8$$

Combine \frac{9}{5}x and 96x to get \frac{489}{5}x.

$$\frac{489}{5}x-9=79.8$$

Add 9 to both sides.

$$\frac{489}{5}x=79.8+9$$

Add 79.8 and 9 to get 88.8.

$$\frac{489}{5}x=88.8$$

Multiply both sides by \frac{5}{489}, the reciprocal of \frac{489}{5}.

$$x=88.8\times \frac{5}{489}$$

Convert decimal number 88.8 to fraction \frac{888}{10}. Reduce the fraction \frac{888}{10} to lowest terms by extracting and canceling out 2.

$$x=\frac{444}{5}\times \frac{5}{489}$$

Multiply \frac{444}{5} times \frac{5}{489} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{444\times 5}{5\times 489}$$

Cancel out 5 in both numerator and denominator.

$$x=\frac{444}{489}$$

Reduce the fraction \frac{444}{489} to lowest terms by extracting and canceling out 3.

$$x=\frac{148}{163}$$