Solve 9/49*1/2+17/29*1/2

$$\frac { 9 } { 49 } \times \frac { 1 } { 2 } + \frac { 17 } { 29 } \times \frac { 1 } { 2 }$$

Evaluate

$$\frac{547}{1421}\approx 0.384940183$$

Solution Steps

Multiply \frac{9}{49} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9\times 1}{49\times 2}+\frac{17}{29}\times \frac{1}{2}$$

Do the multiplications in the fraction \frac{9\times 1}{49\times 2}.

$$\frac{9}{98}+\frac{17}{29}\times \frac{1}{2}$$

Multiply \frac{17}{29} times \frac{1}{2} by multiplying numerator times numerator and denominator times denominator.

$$\frac{9}{98}+\frac{17\times 1}{29\times 2}$$

Do the multiplications in the fraction \frac{17\times 1}{29\times 2}.

$$\frac{9}{98}+\frac{17}{58}$$

Least common multiple of 98 and 58 is 2842. Convert \frac{9}{98} and \frac{17}{58} to fractions with denominator 2842.

$$\frac{261}{2842}+\frac{833}{2842}$$

Since \frac{261}{2842} and \frac{833}{2842} have the same denominator, add them by adding their numerators.

$$\frac{261+833}{2842}$$

Add 261 and 833 to get 1094.

$$\frac{1094}{2842}$$

Reduce the fraction \frac{1094}{2842} to lowest terms by extracting and canceling out 2.

$$\frac{547}{1421}$$

Factor

$$\frac{547}{7 ^ {2} \cdot 29} = 0.38494018296973964$$