Solve 9/4-6+3/2+3=

$$\frac { 9 } { 4 } - 6 + \frac { 3 } { 2 } + 3 =$$

Evaluate

$$\frac{3}{4}=0.75$$

Solution Steps

Convert 6 to fraction \frac{24}{4}.

$$\frac{9}{4}-\frac{24}{4}+\frac{3}{2}+3$$

Since \frac{9}{4} and \frac{24}{4} have the same denominator, subtract them by subtracting their numerators.

$$\frac{9-24}{4}+\frac{3}{2}+3$$

Subtract 24 from 9 to get -15.

$$-\frac{15}{4}+\frac{3}{2}+3$$

Least common multiple of 4 and 2 is 4. Convert -\frac{15}{4} and \frac{3}{2} to fractions with denominator 4.

$$-\frac{15}{4}+\frac{6}{4}+3$$

Since -\frac{15}{4} and \frac{6}{4} have the same denominator, add them by adding their numerators.

$$\frac{-15+6}{4}+3$$

Add -15 and 6 to get -9.

$$-\frac{9}{4}+3$$

Convert 3 to fraction \frac{12}{4}.

$$-\frac{9}{4}+\frac{12}{4}$$

Since -\frac{9}{4} and \frac{12}{4} have the same denominator, add them by adding their numerators.

$$\frac{-9+12}{4}$$

Add -9 and 12 to get 3.

$$\frac{3}{4}$$

Factor

$$\frac{3}{2 ^ {2}} = 0.75$$