Solve 9/4,2/6,94/8

$$\frac { 9 } { 4 } , \frac { 2 } { 6 } , \frac { 94 } { 8 }$$

Sort

$$\frac{1}{3},\frac{9}{4},\frac{47}{4}$$

Solution Steps

Reduce the fraction \frac{2}{6} to lowest terms by extracting and canceling out 2.

$$sort(\frac{9}{4},\frac{1}{3},\frac{94}{8})$$

Reduce the fraction \frac{94}{8} to lowest terms by extracting and canceling out 2.

$$sort(\frac{9}{4},\frac{1}{3},\frac{47}{4})$$

Least common denominator of the numbers in the list \frac{9}{4},\frac{1}{3},\frac{47}{4} is 12. Convert numbers in the list to fractions with denominator 12.

$$\frac{27}{12},\frac{4}{12},\frac{141}{12}$$

To sort the list, start from a single element \frac{27}{12}.

$$\frac{27}{12}$$

Insert \frac{4}{12} to the appropriate location in the new list.

$$\frac{4}{12},\frac{27}{12}$$

Insert \frac{141}{12} to the appropriate location in the new list.

$$\frac{4}{12},\frac{27}{12},\frac{141}{12}$$

Replace the obtained fractions with the initial values.

$$\frac{1}{3},\frac{9}{4},\frac{47}{4}$$

Evaluate

$$\frac{9}{4},\frac{1}{3},\frac{47}{4}$$