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\frac{9m^{2}-400n^{2}}{25}
Factor out \frac{1}{25}.
\left(3m-20n\right)\left(3m+20n\right)
Consider 9m^{2}-400n^{2}. Rewrite 9m^{2}-400n^{2} as \left(3m\right)^{2}-\left(20n\right)^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
\frac{\left(3m-20n\right)\left(3m+20n\right)}{25}
Rewrite the complete factored expression.