Solve 9/2x+2+4/3x+3

$$\frac { 9 } { 2 x + 2 } + \frac { 4 } { 3 x + 3 }$$

Evaluate

$$\frac{35}{6\left(x+1\right)}$$

Short Solution Steps

Factor 2x+2. Factor 3x+3.

$$\frac{9}{2\left(x+1\right)}+\frac{4}{3\left(x+1\right)}$$

To add or subtract expressions, expand them to make their denominators the same. Least common multiple of 2\left(x+1\right) and 3\left(x+1\right) is 6\left(x+1\right). Multiply \frac{9}{2\left(x+1\right)} times \frac{3}{3}. Multiply \frac{4}{3\left(x+1\right)} times \frac{2}{2}.

$$\frac{9\times 3}{6\left(x+1\right)}+\frac{4\times 2}{6\left(x+1\right)}$$

Since \frac{9\times 3}{6\left(x+1\right)} and \frac{4\times 2}{6\left(x+1\right)} have the same denominator, add them by adding their numerators.

$$\frac{9\times 3+4\times 2}{6\left(x+1\right)}$$

Do the multiplications in 9\times 3+4\times 2.

$$\frac{27+8}{6\left(x+1\right)}$$

Do the calculations in 27+8.

$$\frac{35}{6\left(x+1\right)}$$

Expand 6\left(x+1\right).

$$\frac{35}{6x+6}$$

Factor

$$\frac{35}{6\left(x+1\right)}$$