Solve 9/2x-6y-3=0

$$\frac { 9 } { 2 } x - 6 y - 3 = 0$$

Solve for x

$$x=\frac{4y+2}{3}$$

Steps for Solving Linear Equation

Add 6y to both sides. Anything plus zero gives itself.

$$\frac{9}{2}x-3=6y$$

Add 3 to both sides.

$$\frac{9}{2}x=6y+3$$

Divide both sides of the equation by \frac{9}{2}, which is the same as multiplying both sides by the reciprocal of the fraction.

$$\frac{\frac{9}{2}x}{\frac{9}{2}}=\frac{6y+3}{\frac{9}{2}}$$

Dividing by \frac{9}{2} undoes the multiplication by \frac{9}{2}.

$$x=\frac{6y+3}{\frac{9}{2}}$$

Divide 6y+3 by \frac{9}{2} by multiplying 6y+3 by the reciprocal of \frac{9}{2}.

$$x=\frac{4y+2}{3}$$

Solve for y

$$y=\frac{3x}{4}-\frac{1}{2}$$

Steps for Solving Linear Equation

Subtract \frac{9}{2}x from both sides. Anything subtracted from zero gives its negation.

$$-6y-3=-\frac{9}{2}x$$

Add 3 to both sides.

$$-6y=-\frac{9}{2}x+3$$

The equation is in standard form.

$$-6y=-\frac{9x}{2}+3$$

Divide both sides by -6.

$$\frac{-6y}{-6}=\frac{-\frac{9x}{2}+3}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$y=\frac{-\frac{9x}{2}+3}{-6}$$

Divide -\frac{9x}{2}+3 by -6.

$$y=\frac{3x}{4}-\frac{1}{2}$$