Solve 9/16+3/8+1/48

$$\frac { 9 } { 16 } + \frac { 3 } { 8 } + \frac { 1 } { 48 }$$

Evaluate

$$\frac{23}{24}\approx 0.958333333$$

Solution Steps

Least common multiple of 16 and 8 is 16. Convert \frac{9}{16} and \frac{3}{8} to fractions with denominator 16.

$$\frac{9}{16}+\frac{6}{16}+\frac{1}{48}$$

Since \frac{9}{16} and \frac{6}{16} have the same denominator, add them by adding their numerators.

$$\frac{9+6}{16}+\frac{1}{48}$$

Add 9 and 6 to get 15.

$$\frac{15}{16}+\frac{1}{48}$$

Least common multiple of 16 and 48 is 48. Convert \frac{15}{16} and \frac{1}{48} to fractions with denominator 48.

$$\frac{45}{48}+\frac{1}{48}$$

Since \frac{45}{48} and \frac{1}{48} have the same denominator, add them by adding their numerators.

$$\frac{45+1}{48}$$

Add 45 and 1 to get 46.

$$\frac{46}{48}$$

Reduce the fraction \frac{46}{48} to lowest terms by extracting and canceling out 2.

$$\frac{23}{24}$$

Factor

$$\frac{23}{2 ^ {3} \cdot 3} = 0.9583333333333334$$