Evaluate
\frac{21}{40}=0.525
Factor
\frac{3 \cdot 7}{2 ^ {3} \cdot 5} = 0.525
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\frac{36}{40}-\frac{15}{40}
Least common multiple of 10 and 8 is 40. Convert \frac{9}{10} and \frac{3}{8} to fractions with denominator 40.
\frac{36-15}{40}
Since \frac{36}{40} and \frac{15}{40} have the same denominator, subtract them by subtracting their numerators.
\frac{21}{40}
Subtract 15 from 36 to get 21.
Examples
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{ x } ^ { 2 } - 4 x - 5 = 0
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y = 3x + 4
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Matrix
\left[ \begin{array} { l l } { 2 } & { 3 } \\ { 5 } & { 4 } \end{array} \right] \left[ \begin{array} { l l l } { 2 } & { 0 } & { 3 } \\ { -1 } & { 1 } & { 5 } \end{array} \right]
Simultaneous equation
\left. \begin{cases} { 8x+2y = 46 } \\ { 7x+3y = 47 } \end{cases} \right.
Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
\int _ { 0 } ^ { 1 } x e ^ { - x ^ { 2 } } d x
Limits
\lim _{x \rightarrow-3} \frac{x^{2}-9}{x^{2}+2 x-3}