Solve 9*3*3-(21)/(3^2)^5*2^3

$$\frac { 9 \times 3 \times 3 - ( 21 ) } { ( 3 ^ { 2 } ) ^ { 5 } \times 2 ^ { 3 } }$$

Evaluate

$$\frac{5}{39366}\approx 0.000127013$$

Solution Steps

To raise a power to another power, multiply the exponents. Multiply 2 and 5 to get 10.

$$\frac{9\times 3\times 3-21}{3^{10}\times 2^{3}}$$

Multiply 9 and 3 to get 27.

$$\frac{27\times 3-21}{3^{10}\times 2^{3}}$$

Multiply 27 and 3 to get 81.

$$\frac{81-21}{3^{10}\times 2^{3}}$$

Subtract 21 from 81 to get 60.

$$\frac{60}{3^{10}\times 2^{3}}$$

Calculate 3 to the power of 10 and get 59049.

$$\frac{60}{59049\times 2^{3}}$$

Calculate 2 to the power of 3 and get 8.

$$\frac{60}{59049\times 8}$$

Multiply 59049 and 8 to get 472392.

$$\frac{60}{472392}$$

Reduce the fraction \frac{60}{472392} to lowest terms by extracting and canceling out 12.

$$\frac{5}{39366}$$

Factor

$$\frac{5}{2 \cdot 3 ^ {9}} = 0.00012701315856322715$$