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\frac{9\sqrt{3}}{2}\times \frac{\sqrt{7}}{3\left(\sqrt{7}\right)^{2}}
Rationalize the denominator of \frac{1}{3\sqrt{7}} by multiplying numerator and denominator by \sqrt{7}.
\frac{9\sqrt{3}}{2}\times \frac{\sqrt{7}}{3\times 7}
The square of \sqrt{7} is 7.
\frac{9\sqrt{3}}{2}\times \frac{\sqrt{7}}{21}
Multiply 3 and 7 to get 21.
\frac{9\sqrt{3}\sqrt{7}}{2\times 21}
Multiply \frac{9\sqrt{3}}{2} times \frac{\sqrt{7}}{21} by multiplying numerator times numerator and denominator times denominator.
\frac{3\sqrt{3}\sqrt{7}}{2\times 7}
Cancel out 3 in both numerator and denominator.
\frac{3\sqrt{21}}{2\times 7}
To multiply \sqrt{3} and \sqrt{7}, multiply the numbers under the square root.
\frac{3\sqrt{21}}{14}
Multiply 2 and 7 to get 14.