Solve 95/3/3-5frac{5{3}}

$$\frac { 9 \frac { 5 } { 3 } } { 3 - 5 \frac { 5 } { 3 } }$$

Evaluate

$$-\frac{32}{11}\approx -2.909090909$$

Solution Steps

Multiply 9 and 3 to get 27.

$$\frac{\frac{27+5}{3}}{3-\frac{5\times 3+5}{3}}$$

Add 27 and 5 to get 32.

$$\frac{\frac{32}{3}}{3-\frac{5\times 3+5}{3}}$$

Multiply 5 and 3 to get 15.

$$\frac{\frac{32}{3}}{3-\frac{15+5}{3}}$$

Add 15 and 5 to get 20.

$$\frac{\frac{32}{3}}{3-\frac{20}{3}}$$

Convert 3 to fraction \frac{9}{3}.

$$\frac{\frac{32}{3}}{\frac{9}{3}-\frac{20}{3}}$$

Since \frac{9}{3} and \frac{20}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{\frac{32}{3}}{\frac{9-20}{3}}$$

Subtract 20 from 9 to get -11.

$$\frac{\frac{32}{3}}{-\frac{11}{3}}$$

Divide \frac{32}{3} by -\frac{11}{3} by multiplying \frac{32}{3} by the reciprocal of -\frac{11}{3}.

$$\frac{32}{3}\left(-\frac{3}{11}\right)$$

Multiply \frac{32}{3} times -\frac{3}{11} by multiplying numerator times numerator and denominator times denominator.

$$\frac{32\left(-3\right)}{3\times 11}$$

Do the multiplications in the fraction \frac{32\left(-3\right)}{3\times 11}.

$$\frac{-96}{33}$$

Reduce the fraction \frac{-96}{33} to lowest terms by extracting and canceling out 3.

$$-\frac{32}{11}$$

Factor

$$-\frac{32}{11} = -2\frac{10}{11} = -2.909090909090909$$