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\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{1}{x+1}+\frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Factor x^{3}+1.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}-x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}+\frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and \left(x+1\right)\left(x^{2}-x+1\right) is \left(x+1\right)\left(x^{2}-x+1\right). Multiply \frac{1}{x+1} times \frac{x^{2}-x+1}{x^{2}-x+1}.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}-x+1+3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Since \frac{x^{2}-x+1}{\left(x+1\right)\left(x^{2}-x+1\right)} and \frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)} have the same denominator, add them by adding their numerators.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}+2x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Combine like terms in x^{2}-x+1+3x.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{\left(x+1\right)^{2}}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Factor the expressions that are not already factored in \frac{x^{2}+2x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x+1}{x^{2}-x+1}}
Cancel out x+1 in both numerator and denominator.
\frac{\left(9x+a\right)\left(x^{2}-x+1\right)}{\left(x^{2}-x+1\right)\left(x+1\right)}
Divide \frac{9x+a}{x^{2}-x+1} by \frac{x+1}{x^{2}-x+1} by multiplying \frac{9x+a}{x^{2}-x+1} by the reciprocal of \frac{x+1}{x^{2}-x+1}.
\frac{9x+a}{x+1}
Cancel out x^{2}-x+1 in both numerator and denominator.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{1}{x+1}+\frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Factor x^{3}+1.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}-x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}+\frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of x+1 and \left(x+1\right)\left(x^{2}-x+1\right) is \left(x+1\right)\left(x^{2}-x+1\right). Multiply \frac{1}{x+1} times \frac{x^{2}-x+1}{x^{2}-x+1}.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}-x+1+3x}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Since \frac{x^{2}-x+1}{\left(x+1\right)\left(x^{2}-x+1\right)} and \frac{3x}{\left(x+1\right)\left(x^{2}-x+1\right)} have the same denominator, add them by adding their numerators.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x^{2}+2x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Combine like terms in x^{2}-x+1+3x.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{\left(x+1\right)^{2}}{\left(x+1\right)\left(x^{2}-x+1\right)}}
Factor the expressions that are not already factored in \frac{x^{2}+2x+1}{\left(x+1\right)\left(x^{2}-x+1\right)}.
\frac{\frac{9x+a}{x^{2}-x+1}}{\frac{x+1}{x^{2}-x+1}}
Cancel out x+1 in both numerator and denominator.
\frac{\left(9x+a\right)\left(x^{2}-x+1\right)}{\left(x^{2}-x+1\right)\left(x+1\right)}
Divide \frac{9x+a}{x^{2}-x+1} by \frac{x+1}{x^{2}-x+1} by multiplying \frac{9x+a}{x^{2}-x+1} by the reciprocal of \frac{x+1}{x^{2}-x+1}.
\frac{9x+a}{x+1}
Cancel out x^{2}-x+1 in both numerator and denominator.