Solve 9*2+4*11+(-2)*(10)/56*sqrt{15}

$$\frac { 9 \cdot 2 + 4 \cdot 11 + ( - 2 ) \cdot ( 10 ) } { 56 \cdot \sqrt { 15 } }$$

Evaluate

$$\frac{\sqrt{15}}{20}\approx 0.193649167$$

Solution Steps

Multiply 9 and 2 to get 18. Multiply 4 and 11 to get 44. Multiply -2 and 10 to get -20.

$$\frac{18+44-20}{56\sqrt{15}}$$

Add 18 and 44 to get 62.

$$\frac{62-20}{56\sqrt{15}}$$

Subtract 20 from 62 to get 42.

$$\frac{42}{56\sqrt{15}}$$

Rationalize the denominator of \frac{42}{56\sqrt{15}} by multiplying numerator and denominator by \sqrt{15}.

$$\frac{42\sqrt{15}}{56\left(\sqrt{15}\right)^{2}}$$

The square of \sqrt{15} is 15.

$$\frac{42\sqrt{15}}{56\times 15}$$

Cancel out 3\times 14 in both numerator and denominator.

$$\frac{\sqrt{15}}{4\times 5}$$

Multiply 4 and 5 to get 20.

$$\frac{\sqrt{15}}{20}$$