Solve 9^3*27^4*3^-7/frac{1{3}*243^2}

$$\frac { 9 ^ { 3 } \cdot 27 ^ { 4 } \cdot 3 ^ { - 7 } } { \frac { 1 } { 3 } \cdot 243 ^ { 2 } }$$

Evaluate

$$9$$

Solution Steps

Calculate 9 to the power of 3 and get 729.

$$\frac{729\times 27^{4}\times 3^{-7}}{\frac{1}{3}\times 243^{2}}$$

Calculate 27 to the power of 4 and get 531441.

$$\frac{729\times 531441\times 3^{-7}}{\frac{1}{3}\times 243^{2}}$$

Multiply 729 and 531441 to get 387420489.

$$\frac{387420489\times 3^{-7}}{\frac{1}{3}\times 243^{2}}$$

Calculate 3 to the power of -7 and get \frac{1}{2187}.

$$\frac{387420489\times \frac{1}{2187}}{\frac{1}{3}\times 243^{2}}$$

Multiply 387420489 and \frac{1}{2187} to get 177147.

$$\frac{177147}{\frac{1}{3}\times 243^{2}}$$

Calculate 243 to the power of 2 and get 59049.

$$\frac{177147}{\frac{1}{3}\times 59049}$$

Multiply \frac{1}{3} and 59049 to get 19683.

$$\frac{177147}{19683}$$

Divide 177147 by 19683 to get 9.

$$9$$

Factor

$$3^{2}$$