Solve 81/88*(6-113/15*119/21)

$$\frac { 81 } { 88 } \cdot ( 6 - 1 \frac { 13 } { 15 } \cdot 1 \frac { 19 } { 21 } )$$

Evaluate

$$\frac{9}{4}=2.25$$

Solution Steps

Multiply 1 and 15 to get 15.

$$\frac{81}{88}\left(6-\frac{15+13}{15}\times \frac{1\times 21+19}{21}\right)$$

Add 15 and 13 to get 28.

$$\frac{81}{88}\left(6-\frac{28}{15}\times \frac{1\times 21+19}{21}\right)$$

Multiply 1 and 21 to get 21.

$$\frac{81}{88}\left(6-\frac{28}{15}\times \frac{21+19}{21}\right)$$

Add 21 and 19 to get 40.

$$\frac{81}{88}\left(6-\frac{28}{15}\times \frac{40}{21}\right)$$

Multiply \frac{28}{15} times \frac{40}{21} by multiplying numerator times numerator and denominator times denominator.

$$\frac{81}{88}\left(6-\frac{28\times 40}{15\times 21}\right)$$

Do the multiplications in the fraction \frac{28\times 40}{15\times 21}.

$$\frac{81}{88}\left(6-\frac{1120}{315}\right)$$

Reduce the fraction \frac{1120}{315} to lowest terms by extracting and canceling out 35.

$$\frac{81}{88}\left(6-\frac{32}{9}\right)$$

Convert 6 to fraction \frac{54}{9}.

$$\frac{81}{88}\left(\frac{54}{9}-\frac{32}{9}\right)$$

Since \frac{54}{9} and \frac{32}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{81}{88}\times \frac{54-32}{9}$$

Subtract 32 from 54 to get 22.

$$\frac{81}{88}\times \frac{22}{9}$$

Multiply \frac{81}{88} times \frac{22}{9} by multiplying numerator times numerator and denominator times denominator.

$$\frac{81\times 22}{88\times 9}$$

Do the multiplications in the fraction \frac{81\times 22}{88\times 9}.

$$\frac{1782}{792}$$

Reduce the fraction \frac{1782}{792} to lowest terms by extracting and canceling out 198.

$$\frac{9}{4}$$

Factor

$$\frac{3 ^ {2}}{2 ^ {2}} = 2\frac{1}{4} = 2.25$$