Solve 80/243+32/81+8/9-1/3

$$\frac { 80 } { 243 } + \frac { 32 } { 81 } + \frac { 8 } { 9 } - \frac { 1 } { 3 }$$

Evaluate

$$\frac{311}{243}\approx 1.279835391$$

Solution Steps

Least common multiple of 243 and 81 is 243. Convert \frac{80}{243} and \frac{32}{81} to fractions with denominator 243.

$$\frac{80}{243}+\frac{96}{243}+\frac{8}{9}-\frac{1}{3}$$

Since \frac{80}{243} and \frac{96}{243} have the same denominator, add them by adding their numerators.

$$\frac{80+96}{243}+\frac{8}{9}-\frac{1}{3}$$

Add 80 and 96 to get 176.

$$\frac{176}{243}+\frac{8}{9}-\frac{1}{3}$$

Least common multiple of 243 and 9 is 243. Convert \frac{176}{243} and \frac{8}{9} to fractions with denominator 243.

$$\frac{176}{243}+\frac{216}{243}-\frac{1}{3}$$

Since \frac{176}{243} and \frac{216}{243} have the same denominator, add them by adding their numerators.

$$\frac{176+216}{243}-\frac{1}{3}$$

Add 176 and 216 to get 392.

$$\frac{392}{243}-\frac{1}{3}$$

Least common multiple of 243 and 3 is 243. Convert \frac{392}{243} and \frac{1}{3} to fractions with denominator 243.

$$\frac{392}{243}-\frac{81}{243}$$

Since \frac{392}{243} and \frac{81}{243} have the same denominator, subtract them by subtracting their numerators.

$$\frac{392-81}{243}$$

Subtract 81 from 392 to get 311.

$$\frac{311}{243}$$

Factor

$$\frac{311}{3 ^ {5}} = 1\frac{68}{243} = 1.2798353909465021$$