Solve 8y/12y-18y^2

$$\frac { 8 y } { 12 y - 18 y ^ { 2 } }$$

Evaluate

$$\frac{4}{3\left(2-3y\right)}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{8y}{6y\left(-3y+2\right)}$$

Cancel out 2y in both numerator and denominator.

$$\frac{4}{3\left(-3y+2\right)}$$

Expand the expression.

$$\frac{4}{-9y+6}$$

Differentiate w.r.t. y

$$\frac{4}{\left(2-3y\right)^{2}}$$

Steps Using Derivative Rule for Quotient

For any two differentiable functions, the derivative of the quotient of two functions is the denominator times the derivative of the numerator minus the numerator times the derivative of the denominator, all divided by the denominator squared.

$$\frac{\left(12y^{1}-18y^{2}\right)\frac{\mathrm{d}}{\mathrm{d}y}(8y^{1})-8y^{1}\frac{\mathrm{d}}{\mathrm{d}y}(12y^{1}-18y^{2})}{\left(12y^{1}-18y^{2}\right)^{2}}$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$\frac{\left(12y^{1}-18y^{2}\right)\times 8y^{1-1}-8y^{1}\left(12y^{1-1}+2\left(-18\right)y^{2-1}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

Simplify.

$$\frac{\left(12y^{1}-18y^{2}\right)\times 8y^{0}-8y^{1}\left(12y^{0}-36y^{1}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

Multiply 12y^{1}-18y^{2} times 8y^{0}.

$$\frac{12y^{1}\times 8y^{0}-18y^{2}\times 8y^{0}-8y^{1}\left(12y^{0}-36y^{1}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

Multiply 8y^{1} times 12y^{0}-36y^{1}.

$$\frac{12y^{1}\times 8y^{0}-18y^{2}\times 8y^{0}-\left(8y^{1}\times 12y^{0}+8y^{1}\left(-36\right)y^{1}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

To multiply powers of the same base, add their exponents.

$$\frac{12\times 8y^{1}-18\times 8y^{2}-\left(8\times 12y^{1}+8\left(-36\right)y^{1+1}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

Simplify.

$$\frac{96y^{1}-144y^{2}-\left(96y^{1}-288y^{2}\right)}{\left(12y^{1}-18y^{2}\right)^{2}}$$

Combine like terms.

$$\frac{144y^{2}}{\left(12y^{1}-18y^{2}\right)^{2}}$$

For any term t, t^{1}=t.

$$\frac{144y^{2}}{\left(12y-18y^{2}\right)^{2}}$$