Solve 8x^6-10x^4-12x^3/-4x^2

$$\frac { 8 x ^ { 6 } - 10 x ^ { 4 } - 12 x ^ { 3 } } { - 4 x ^ { 2 } }$$

Evaluate

$$\frac{x\left(6+5x-4x^{3}\right)}{2}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{2^{2}\left(2x-3\right)\left(x^{2}+\frac{3}{2}x+1\right)x^{3}}{-4x^{2}}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{2^{2}x\left(2x-3\right)\left(x^{2}+\frac{3}{2}x+1\right)}{-4}$$

Expand the expression.

$$\frac{8x^{4}-10x^{2}-12x}{-4}$$

Expand

$$-2x^{4}+\frac{5x^{2}}{2}+3x$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{2^{2}\left(2x-3\right)\left(x^{2}+\frac{3}{2}x+1\right)x^{3}}{-4x^{2}}$$

Cancel out x^{2} in both numerator and denominator.

$$\frac{2^{2}x\left(2x-3\right)\left(x^{2}+\frac{3}{2}x+1\right)}{-4}$$

Expand the expression.

$$\frac{8x^{4}-10x^{2}-12x}{-4}$$