Solve 8t^3-12t^2+6t-9/16t^4-9

$$\frac { 8 t ^ { 3 } - 12 t ^ { 2 } + 6 t - 9 } { 16 t ^ { 4 } - 9 }$$

Evaluate

$$\frac{2t-3}{4t^{2}-3}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(2t-3\right)\left(4t^{2}+3\right)}{\left(4t^{2}-3\right)\left(4t^{2}+3\right)}$$

Cancel out 4t^{2}+3 in both numerator and denominator.

$$\frac{2t-3}{4t^{2}-3}$$

Expand

$$\frac{2t-3}{4t^{2}-3}$$

Short Solution Steps

Factor the expressions that are not already factored.

$$\frac{\left(2t-3\right)\left(4t^{2}+3\right)}{\left(4t^{2}-3\right)\left(4t^{2}+3\right)}$$

Cancel out 4t^{2}+3 in both numerator and denominator.

$$\frac{2t-3}{4t^{2}-3}$$