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Evaluate
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Differentiate w.r.t. b
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\frac{8b^{3}}{8}\times 1
Divide 8 by 8 to get 1.
b^{3}\times 1
Cancel out 8 and 8.
b^{3}
For any term t, t\times 1=t and 1t=t.
\frac{\mathrm{d}}{\mathrm{d}b}(\frac{8b^{3}}{8}\times 1)
Divide 8 by 8 to get 1.
\frac{\mathrm{d}}{\mathrm{d}b}(b^{3}\times 1)
Cancel out 8 and 8.
3b^{3-1}
The derivative of ax^{n} is nax^{n-1}.
3b^{2}
Subtract 1 from 3.