Solve 8b^2/b

$$\frac { 8 b ^ { 2 } } { b }$$

Differentiate w.r.t. b

$$8$$

Steps Using Derivative Rule for Product

For any two differentiable functions, the derivative of the product of two functions is the first function times the derivative of the second plus the second function times the derivative of the first.

$$8b^{2}\frac{\mathrm{d}}{\mathrm{d}b}(\frac{1}{b})+\frac{1}{b}\frac{\mathrm{d}}{\mathrm{d}b}(8b^{2})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8b^{2}\left(-1\right)b^{-1-1}+\frac{1}{b}\times 2\times 8b^{2-1}$$

Simplify.

$$8b^{2}\left(-1\right)b^{-2}+\frac{1}{b}\times 16b^{1}$$

To multiply powers of the same base, add their exponents.

$$-8b^{2-2}+16b^{-1+1}$$

Simplify.

$$-8b^{0}+16b^{0}$$

For any term t except 0, t^{0}=1.

$$-8+16\times 1$$

For any term t, t\times 1=t and 1t=t.

$$-8+16$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent.

$$\frac{\mathrm{d}}{\mathrm{d}b}(\frac{8}{1}b^{2-1})$$

Do the arithmetic.

$$\frac{\mathrm{d}}{\mathrm{d}b}(8b^{1})$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$8b^{1-1}$$

Do the arithmetic.

$$8b^{0}$$

For any term t except 0, t^{0}=1.

$$8\times 1$$

For any term t, t\times 1=t and 1t=t.

$$8$$

Evaluate

$$8b$$

Solution Steps

Cancel out b in both numerator and denominator.

$$8b$$