Solve 8-3/7^2-1-1/1-11

$$\frac { 8 - 3 } { 7 ^ { 2 } - 1 } - \frac { 1 } { 1 - 11 }$$

Evaluate

$$\frac{49}{240}\approx 0.204166667$$

Solution Steps

Subtract 3 from 8 to get 5.

$$\frac{5}{7^{2}-1}-\frac{1}{1-11}$$

Calculate 7 to the power of 2 and get 49.

$$\frac{5}{49-1}-\frac{1}{1-11}$$

Subtract 1 from 49 to get 48.

$$\frac{5}{48}-\frac{1}{1-11}$$

Subtract 11 from 1 to get -10.

$$\frac{5}{48}-\frac{1}{-10}$$

Fraction \frac{1}{-10} can be rewritten as -\frac{1}{10} by extracting the negative sign.

$$\frac{5}{48}-\left(-\frac{1}{10}\right)$$

The opposite of -\frac{1}{10} is \frac{1}{10}.

$$\frac{5}{48}+\frac{1}{10}$$

Least common multiple of 48 and 10 is 240. Convert \frac{5}{48} and \frac{1}{10} to fractions with denominator 240.

$$\frac{25}{240}+\frac{24}{240}$$

Since \frac{25}{240} and \frac{24}{240} have the same denominator, add them by adding their numerators.

$$\frac{25+24}{240}$$

Add 25 and 24 to get 49.

$$\frac{49}{240}$$

Factor

$$\frac{7 ^ {2}}{2 ^ {4} \cdot 3 \cdot 5} = 0.20416666666666666$$